# JBL AEO Written Exam Question Solution 2020

JBL AEO Written Exam Question Solution 2020, Janata Bank Limited Assistant Executive officer (AEO) Written Question Solution 2020, JBL AEO post written Question solution, JBL Job Exam question Solution 2020, Bank Exam question solution 2020, JBL Written Exam question Full Solution 2020.

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## JBL AEO Written Exam Question Solution 2020

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## JBL AEO Written Exam Question Solution 2020

#### Post Name And Vacancy:

1. Assistant Executive officer (AEO)- 464

MCQ Exam Date: 29 November 2019

Exam Time: 10.00 AM – 11.00 AM

Written Exam Date: 10 January 2020

Written Exam Time: 10.00 AM to 12.00 AM

Solved it by Jobstestbd.com ABD Mamin

1. A sum of taka 725 is lent in the beginning of a year at a certain rate of interest. After 8 months , a sum of tk 362.50 more is lent but at the rate of twice the former. At the end of the year Tk 33.50 is earned as interest from both the loans. what was the original rate of Interest?

Ans: 3.46% (Approximately)

Detail Full Solution:

Let, Initial Rate = r%
Final rate = 2r%
ATQ,
725*1* r/100+ (362.5)*(1/3)*2r/100= 33.50
=> 725r+ 241.67r= 3350
=> r= 3.46%

2. If x+1/x=2; find the value of x^17+1/(x^19)=?

Ans: 2

Detail Full Solution:

x+ 1/x = 2
=> x^2+1= 2x
=> x^2-2x+1= 0
=> x^2-x-x+1= 0
=> x(x-1)-1(x-1)= 0
=> x= 1

Now,
x^17+ 1/x^19
= (1)^17+1/(1)^19
= 1+1
= 2

3. Two men X and Y started working for a certain company at similar jobs on January 1, 1950. X asked for an initial salary of Rs. 300 with an annual increment of Rs. 30. Y asked for an initial salary of Rs. 200 with a rise of Rs. 15 every six months. Assume that the arrangements remained unaltered till December 31, 1959. Salary is paid on the last day of the month. What is the total amount paid to them as salary during the period?

Ans: 93,300

Detail Full Solution:

X salary for first year = 12*300= 3600 for first year
Salary up to 1959 = (3600+3960+———–+n)
Here, n= 10
a = 3600
d= 360
Total salary = 10/2*{2*3600+(10-1)*360}
= 5{7200+9*360}= 52,200

Y salary up to 1959
= 1200 for 6 month
= 1200+ 15*6= 1290 for next six month

Total salary of Y = 20/2*{2*1200+19*90}
= 41,100
Total Salary = (52,200+41,100)
= 93,300

4. In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is?

Ans: 1 Hour

Detail Full Solution:

Let the duration of the flight be x hours.  x(2x + 1) = 3 2x2 + x – 3 = 0 (2x + 3)(x – 1) = 0 x = 1 hr.      [neglecting the -ve value of x]or,

Flight Distance= 600 km
Let, Avg. Time = t
New time = (t+1/2) hr
ATQ,
600/t – 600/(t+1/2)= 200
=> 600/t – 600/(2t+1)/2= 200
=> 600/t -1200/(2t+1)= 200
=> (1200t+600-1200t)= 200*t(2t+1)
=> 600= 200(2t^2+t)
=> 600= 400t^2+200t
=> 400t^2+200t-600= 0
=>4t^2+2t-6= 0
=> 2t^2+t-3= 0
=> 2t^2+3t-2t-3= 0
=> t(2t+3)-1(2t+3)= 0
So, t= 1hr

5. Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. How many hours will take C alone to fill the tank ?

Ans: 14 hours

Detail Full Solution:

(A+B) can fill = 2/3 part in = 7 hr
1 part in = 21/2 hr
(A+B+C) can 1 part in = 6 hr
Eff. (A+B+C):(A+B)= 7:4
Eff. Of C = 7-4= 3
ATQ,
42= 3*T
=> T= 14 hr

6. A farmer wishes to start a 100 sq.m rectangular vegetable garden. Since he has only 30 m barbed wire, he fences three sides of the garden letting his house compound wall act as the fourth side fencing. The dimension of the garden is?

Ans: 5

Detail Full Solution:

Let, Length and Breadth L& B
Area, L*B= 100
L= 100/B
And,
2L+ B= 30
=> 200/B + B= 30
=> 200+B^2-30B= 0
=> B^2-30B+200= 0
=> B^2-20B-10B+200= 0
=> B= 20,10
If B = 10
L= 10
And, if perimeter, 2B+L= 30
Then, 2B+ 100/B= 30
=> 2B^2-30B+100= 0
=> B^2-15B+50= 0
=> B= 10,5
If B = 5, L = 20
Since, it is rectangular L should be greater than Breadth
So, L= 20
B= 5

7. P does a work in 12 days for 8 hours and Q does a Work in 8 days for 10 hours.If both work for 8 hours then how many days it needed to complete the work ?

Ans: 60/11 days

Detail Full Solution:

12*8*P= 8*10*Q
=> 12P= 10Q
=> P:Q= 5:6
ATQ,
96*5= 8*(5+6)*D
=> 60= 11 D
=> D= 60/11

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